0.5(x^2+1)=x

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Solution for 0.5(x^2+1)=x equation: 



0.5(x^2+1)=x

We move all terms to the left:

0.5(x^2+1)-(x)=0

We add all the numbers together, and all the variables

-1x+0.5(x^2+1)=0

We multiply parentheses

0.5x^2-1x+0.5=0

a = 0.5; b = -1; c = +0.5;
Δ = b2-4ac
Δ = -12-4·0.5·0.5
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{1}{1}=1$

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